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Statistics I, Quiz #4

A survey was conducted of students’ residences. Data was gathered from a random sample of 1000 students. The data is summarized in the table below.

 

Gender and Residence of Students

Males

Females

Apartment off campus

50

90

Dorm room

150

210

With Parent(s)

100

50

Sorority/ Fraternity House

200

150

Start with fractional probabilities, convert to decimals, and round final answers to three decimal places.

 

1.) What is the probability that a student is female and lives in a dorm?

 

The probability of female students living in Dorm room = 210

Total students = 1000

P(female at dorn) = 210/1000

= 0.210

 

2.) What is the probability that a student is female given that she lives in a dorm?

 The probability of female students living in Dorm room = 210

P(female at dorn) = 1/210

= 0.004

 

3.) What is the probability that a student lives in a dorm given that she is a female?

 

Total female students living in a dorn = 210

Total female students =500

P(female student living in dorn) = 210/500

= 0.420

 

4.) What is the probability that a student lives in a dorm or an apartment off campus?

 

Total students living in dorn = 360

Students living in Apartments = 140

Probability= 140/1000

= 0.140

The exercises on the back page relate to the binomial probability distribution. You will need to obtain your answers from MS Excel.

Round final answers to three decimal places.

For each question, you may want to show the data you enter into Excel for partial credit.

number of success

number of trials

probability of success

cumulative probability (true or false) ?

A recent report shows that 80% of elementary school teachers have a computer at home. 12 elementary school teachers are randomly selected.

5.)Find the probability that exactly 10 of them have a home computer.

Probability = 10/12

= 0.8333

6.) Find the probability that 8 or less have a home computer.

P = 8/12

P = 0.666

P is less or equal to 0.666

7.)Find the probability that 12 or fewer have a home computer.

P = 12/12

Probability is equal or less than 1.000

8.) Find the probability that 7 or more have a home computer.

P = 7/12

P = 0.583

Probability is equal to 0.583 or more.

9.)Find the probability that 9 or 10 have a home computer.

P= 9/12

P = 0.750

P= 10/12

P= 0.833

For 9 the probability is 0.750 and for 10 it will be 0.833

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