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Lab Report #3

Aim

To use electric meters to establish the relationship between resistance, current, and voltage

Part A: Verification of the validity of Ohm’s Law

Introduction

According to the Ohms Law V=IR (1)

I=Current measured by Ammeter A= [I] =Amps

V=Voltage as measured by Voltmeter V= [V] =Volts

R= Resistance of the decade-resistance box Ω=[R] = Ohms

Method

Dc circuit is set up as shown in the figure below, and the current and voltage are measured using voltmeter and ammeter

Circuit Diagram

Procedure

The circuit is set up as shown above. By using the cables required, connection to the power supply using the DC range B is made. The connection is made to the convenient range while maximizing needle deflection in the needle in both the ammeter and voltmeter

Resistance is kept constant at 100Ω while voltage is varied as shown in the table and each time measurement of the current is filled in the table.

R constant =100Ω

V

V

1.0

2.0

3.0

4.0

5.0

I

mA

0.01

0.02

0.03

0.04

0.05

Graph of V versus I is drawn with V along the y-axis. The best fitting line is drawn, and the slope is established

Step 2 is repeated while keeping the current constant at 10mA. Resistance is changed and adjust the voltage and the current by turning the black knob of the power supply

Current constant 10 mA

R

Ω

100

200

300

400

500

V

V

1.0

2.0

3.0

4.0

5.0

Draw a graph of V against R with R along the x-axis. The best fitting line is drawn and find the slope

Results

The gradient is Resistance ΔV/ΔA=R =100Ω

Gradient of the graph is Current ΔV/ΔR=I= 0.01A= 10mA

Part B: Measurement of the resistance of the two resistors that are connected in series n and also parallel.

Introduction

When the two resistors are R2, and R1 are connected in series, the equivalent resistance is given by:

Rs=R1+R2 (2)

When the resistors are connected in parallels, the equivalent resistance is provided by

1Rp=1R1+1R2 (3)

Procedure

Connect two resistors of 100Ω in series as shown in the diagram. Voltage is set at 1.0v. The current is then measured I=0.005mA

Using equation 1 find the equivalent resistance

Rs=V/I 200Ω

Using equation 2 found the theoretical value of Rs and compute the percent disparency D

Theoretical value of Rs=100+100 =200Ω

{(200-200)/200}*100=0% disparency

Connect the two 100Ω resistors in parallel as illustrated in the diagram. Voltage is set at 1.0V. The parallel current is measured Ip=0.02mA

Using the equation 1 establish the equivalent resistance

R=V/I=50Ω

Using the equation 3 find the theoretical value for Rp and compute the disparency D

Theoretical value of Rp=50

{(50-50)/50}*100= 0% disparency

Errors

There were no sources of errors since there were 0% disparency

Conclusion

In conclusion electric meters were used to establish the relationship between resistance, current, and voltage.

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