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Lab Report #3
Aim
To use electric meters to establish the relationship between resistance, current, and voltage
Part A: Verification of the validity of Ohm’s Law
Introduction
According to the Ohms Law V=IR (1)
I=Current measured by Ammeter A= [I] =Amps
V=Voltage as measured by Voltmeter V= [V] =Volts
R= Resistance of the decade-resistance box Ω=[R] = Ohms
Method
Dc circuit is set up as shown in the figure below, and the current and voltage are measured using voltmeter and ammeter
Circuit Diagram
Procedure
The circuit is set up as shown above. By using the cables required, connection to the power supply using the DC range B is made. The connection is made to the convenient range while maximizing needle deflection in the needle in both the ammeter and voltmeter
Resistance is kept constant at 100Ω while voltage is varied as shown in the table and each time measurement of the current is filled in the table.
R constant =100Ω
V
V
1.0
2.0
3.0
4.0
5.0
I
mA
0.01
0.02
0.03
0.04
0.05
Graph of V versus I is drawn with V along the y-axis. The best fitting line is drawn, and the slope is established
Step 2 is repeated while keeping the current constant at 10mA. Resistance is changed and adjust the voltage and the current by turning the black knob of the power supply
Current constant 10 mA
R
Ω
100
200
300
400
500
V
V
1.0
2.0
3.0
4.0
5.0
Draw a graph of V against R with R along the x-axis. The best fitting line is drawn and find the slope
Results
The gradient is Resistance ΔV/ΔA=R =100Ω
Gradient of the graph is Current ΔV/ΔR=I= 0.01A= 10mA
Part B: Measurement of the resistance of the two resistors that are connected in series n and also parallel.
Introduction
When the two resistors are R2, and R1 are connected in series, the equivalent resistance is given by:
Rs=R1+R2 (2)
When the resistors are connected in parallels, the equivalent resistance is provided by
1Rp=1R1+1R2 (3)
Procedure
Connect two resistors of 100Ω in series as shown in the diagram. Voltage is set at 1.0v. The current is then measured I=0.005mA
Using equation 1 find the equivalent resistance
Rs=V/I 200Ω
Using equation 2 found the theoretical value of Rs and compute the percent disparency D
Theoretical value of Rs=100+100 =200Ω
{(200-200)/200}*100=0% disparency
Connect the two 100Ω resistors in parallel as illustrated in the diagram. Voltage is set at 1.0V. The parallel current is measured Ip=0.02mA
Using the equation 1 establish the equivalent resistance
R=V/I=50Ω
Using the equation 3 find the theoretical value for Rp and compute the disparency D
Theoretical value of Rp=50
{(50-50)/50}*100= 0% disparency
Errors
There were no sources of errors since there were 0% disparency
Conclusion
In conclusion electric meters were used to establish the relationship between resistance, current, and voltage.
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